The value of the ratio (1 + 122 + 132 + 142 + ….)/(1 − 122 + 132 − 142 + ….) is …… .........
Question
Solution 1
The given series are geometric series.
The first series is 1 + 12^2 + 13^2 + 14^2 + ..., where the common ratio is 12^2.
The sum of an infinite geometric series is given by S = a / (1 - r), where a is the first term and r is the common ratio.
So, the sum of the first series is S1 = 1 / (1 - 12 Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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