Use the quadratic formula to solve 4x 2 = 11x – 5.The solution is:x=−11±41−−√8𝑥=−11±418 x=11±41−−√8𝑥=11±418 x=−11±201−−−√8𝑥=−11±2018 x=11±201−−−√8
Question
Use the quadratic formula to solve 4x 2 = 11x – 5.
The solution is:
- x = −11 ± √41 / 8
- x = 11 ± √41 / 8
- x = −11 ± √20 / 8
- x = 11 ± √20 / 8
Solution
The given equation is 4x^2 = 11x - 5.
First, we need to rearrange the equation into standard quadratic form ax^2 + bx + c = 0.
So, 4x^2 - 11x + 5 = 0.
Now, we can apply the quadratic formula which is x = [-b ± sqrt(b^2 - 4ac)] / (2a).
Here, a = 4, b = -11, and c = 5.
Substituting these values into the quadratic formula gives:
x = [11 ± sqrt((-11)^2 - 445)] / (2*4) x = [11 ± sqrt(121 - 80)] / 8 x = [11 ± sqrt(41)] / 8
So, the solutions of the equation 4x^2 = 11x - 5 are x = (11 + sqrt(41)) / 8 and x = (11 - sqrt(41)) / 8.
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