In the shown figure,  O is the centre of the circle.  PB  =  PC, ∠PBO  =  25∘ and  ∠BOC  =  130∘, then find  ∠ABP + ∠DCP.

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In the shown figure,  O is the centre of the circle.  PB  =  PC, ∠PBO  =  25∘ and  ∠BOC  =  130∘, then find  ∠ABP + ∠DCP.
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In the shown figure,  O is the centre of the circle.  PB  =  PC, ∠PBO  =  25∘ and  ∠BOC  =  130∘, then find  ∠ABP + ∠DCP.

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