If f(x) = 16x2 + bx - 5 and (-5, 315) is an ordered pair that satisfies f(x), what is the value of 5b?(A) -80(B) 80(C) 100(D) 215
Question
If f(x) = 16x² + bx - 5 and (-5, 315) is an ordered pair that satisfies f(x), what is the value of 5b?
(A) -80
(B) 80
(C) 100
(D) 215
Solution
To find the value of 5b, we first need to find the value of b. We can do this by substituting the given ordered pair (-5, 315) into the equation f(x) = 16x^2 + bx - 5.
So, we replace x with -5 and f(x) with 315:
315 = 16(-5)^2 + b(-5) - 5 315 = 16(25) - 5b - 5 315 = 400 - 5b - 5 315 = 395 - 5b
Now, we can solve for b:
5b = 395 - 315 5b = 80
So, the value of 5b is 80. Therefore, the answer is (B) 80.
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