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If the hydronium ion (H3O+) concentration of an aqueous solution at 25°C is 5 × 10−6 M, what is the hydroxide ion (OH–) concentration?

Question

If the hydronium ion (H3O+) concentration of an aqueous solution at 25°C is 5 × 10−6 M, what is the hydroxide ion (OH–) concentration?

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Solution

To find the hydroxide ion (OH-) concentration, we need to use the ion product of water (Kw) at 25°C, which is 1.0 x 10^-14.

The ion product of water (Kw) is given by the equation:

Kw = [H3O+] [OH-]

We know the hydronium ion (H3O+) concentration, which is 5 x 10^-6 M. We can substitute this into the equation and solve for the hydroxide ion (OH-) concentration:

1.0 x 10^-14 = (5 x 10^-6) [OH-]

To solve for [OH-], we divide both sides of the equation by 5 x 10^-6:

[OH-] = (1.0 x 10^-14) / (5 x 10^-6)

[OH-] = 2 x 10^-9 M

So, the hydroxide ion (OH-) concentration is 2 x 10^-9 M.

This problem has been solved

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