Suppose A ≤ C and B ≤ C, then which of the following are true for all such A, B, C:1 pointA union B ≤ CA intersection B ≤ Ccomplement(A) ≤ CC ≤ AC ≤ BA* ≤ C
Question
Suppose A ≤ C and B ≤ C, then which of the following are true for all such A, B, C:
1 point
- A union B ≤ C
- A intersection B ≤ C
- complement(A) ≤ C
- C ≤ A
- C ≤ B
- A* ≤ C
Solution
The question seems to be related to set theory. Here's the step by step analysis:
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A union B ≤ C: This statement is not necessarily true. The union of A and B could potentially include elements that are not in C, even if A and B are subsets of C. For example, if A = {1}, B = {2}, and C = {1}, then A union B = {1, 2}, which is not a subset of C.
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A intersection B ≤ C: This statement is true. The intersection of A and B will only include elements that are in both A and B. Since A and B are subsets of C, their intersection will also be a subset of C.
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complement(A) ≤ C: This statement is not necessarily true. The complement of A includes all elements that are not in A. These elements may or may not be in C.
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C ≤ A: This statement is not necessarily true. The original assumption is that A is a subset of C, not the other way around.
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C ≤ B: This statement is not necessarily true. The original assumption is that B is a subset of C, not the other way around.
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A* ≤ C: This statement is unclear because the notation A* is not standard in set theory. If A* is meant to represent the power set of A (the set of all subsets of A), then the statement is not necessarily true. The power set of A could include subsets that are not in C. If A* represents something else, then the truth of the statement would depend on what A* represents.
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