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If A = {x / 6x2 + x – 15 = 0}, B = {x / 2x2 – 5x – 3 = 0}, C = {x / 2x2 – x – 3 = 0}, then find(i) (A ∪ B ∪ C)(ii) (A ∩ B ∩ C)

Question

If

A = {x / 6x^2 + x – 15 = 0},
B = {x / 2x^2 – 5x – 3 = 0},
C = {x / 2x^2 – x – 3 = 0},
then find
(i) (A ∪ B ∪ C)
(ii) (A ∩ B ∩ C)

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Solution

Sure, let's solve this step by step.

First, we need to find the roots of the equations given in sets A, B, and C.

(i) For set A, the equation is 6x^2 + x - 15 = 0. We can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. The roots of this equation are x = 1.5 and x = -1.67.

(ii) For set B, the equation is 2x^2 - 5x - 3 = 0. Again, we can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. The roots of this equation are x = 3 and x = -0.5.

(iii) For set C, the equation is 2x^2 - x - 3 = 0. We can solve this quadratic equation by factoring, completing the square, or using the quadratic formula. The roots of this equation are x = 1.5 and x = -1.

Now, we can find the union and intersection of these sets.

(i) The union of sets A, B, and C, denoted as A ∪ B ∪ C, is the set of all elements that are in A, or in B, or in C. So, A ∪ B ∪ C = {-1.67, -1, -0.5, 1.5, 3}.

(ii) The intersection of sets A, B, and C, denoted as A ∩ B ∩ C, is the set of all elements that are common to A, B, and C. So, A ∩ B ∩ C = {1.5}.

This problem has been solved

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