What percent of adult women do you expect to have cholesterol levels between 164 mg/dL and 212 mg/dL?

To determine the percentage of adult women expected to have cholesterol levels between 164 mg/dL and 212 mg/dL, we would typically need a description of the data distribution, usually following a normal distribution in health-related statistics.

However, since you haven't provided specific parameters such as the mean and standard deviation of cholesterol levels for adult women, I will describe the general approach you would take to solve this problem:

1. Break Down the Problem

   • Identify the mean and standard deviation of cholesterol levels for adult women.
   • Establish the limits: 164 mg/dL and 212 mg/dL.

2. Relevant Concepts

   • Use the Z-score formula to convert cholesterol levels to Z-scores: $Z = \frac{X - \mu}{\sigma}$ where $X$ is the cholesterol level, $\mu$ is the mean, and $\sigma$ is the standard deviation.

3. Analysis and Detail

   • Calculate the Z-scores for both cholesterol levels:
     • For 164 mg/dL: $Z_{164} = \frac{164 - \mu}{\sigma}$
     • For 212 mg/dL: $Z_{212} = \frac{212 - \mu}{\sigma}$
   • Use the Z-table to find the probability corresponding to each Z-score.
   • Determine the percentage of women with cholesterol levels between these two Z-scores by finding the difference in probability.

4. Verify and Summarize

   • Check the Z-scores calculated against the Z-table and ensure the probabilities are accurately determined.
   • Sum the findings to present the final expectation.

Final Answer

Without the mean and standard deviation, we cannot provide a numerical percentage directly. You need to find the mean $\mu$ and standard deviation $\sigma$ of cholesterol levels among adult women for an accurate calculation based on this approach. If you can provide those values, I could help you compute the expected percentage.