What is the probability of throwing a total of 8 or 11 in a single throw of a pair of dice?

To calculate the probability of throwing a total of 8 or 11 in a single throw of a pair of dice, we first need to know the total number of possible outcomes. When throwing two dice, there are 6 possible outcomes for each die, so the total number of outcomes is 6*6 = 36.

Next, we need to calculate the number of outcomes that result in a total of 8 or 11.

For a total of 8, the possible outcomes are: (2,6), (3,5), (4,4), (5,3), (6,2). So there are 5 outcomes.

For a total of 11, the possible outcomes are: (5,6), (6,5). So there are 2 outcomes.

So the total number of outcomes that result in a total of 8 or 11 is 5 + 2 = 7.

The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. So the probability of throwing a total of 8 or 11 in a single throw of a pair of dice is 7/36 = 0.1944 or 19.44% when rounded to two decimal places.