The radius of a circle is 13 cm and the length of one of its chords is 10 cm. The distance of the chord from the centre is*1 point11.512√6923
Question
The radius of a circle is 13 cm and the length of one of its chords is 10 cm. The distance of the chord from the centre is*1 point11.512√6923
Solution
To solve this problem, we can use the Pythagorean theorem. The theorem states that in a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.
In this case, the radius of the circle is the hypotenuse, the distance from the center of the circle to the chord is one side of the triangle, and half of the chord length is the other side of the triangle.
Given: Radius (r) = 13 cm Chord (c) = 10 cm
We know that the distance from the center to the chord (d) can be found using the formula:
d = sqrt(r^2 - (c/2)^2)
Substituting the given values:
d = sqrt((13)^2 - (10/2)^2) d = sqrt((169) - (25)) d = sqrt(144) d = 12 cm
So, the distance of the chord from the center of the circle is 12 cm.
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