Calculate the Normality of the given 100ml barium chloride titrated against 20ml of 0.02N Sodium sulfate

To calculate the Normality of the given 100ml barium chloride titrated against 20ml of 0.02N Sodium sulfate, we need to use the formula for normality which is:

N1V1 = N2V2

Where: N1 = Normality of the solution 1 (Barium chloride in this case) V1 = Volume of the solution 1 (100ml in this case) N2 = Normality of the solution 2 (0.02N Sodium sulfate in this case) V2 = Volume of the solution 2 (20ml in this case)

We are trying to find N1, so we rearrange the formula to solve for N1:

N1 = N2V2 / V1

Substituting the given values:

N1 = (0.02N * 20ml) / 100ml

N1 = 0.004N

So, the Normality of the given 100ml barium chloride is 0.004N.