A 60-watt light bulb carries a current of 0.5 A. The total charge passing through it in one houris:A. 120 CB. 3600 CC. 3000 CD. 2400 CE. 1800 C
Question
A 60-watt light bulb carries a current of 0.5 A. The total charge passing through it in one hour is:
A. 120 C
B. 3600 C
C. 3000 C
D. 2400 C
E. 1800 C
Solution
The total charge passing through the light bulb can be calculated using the formula Q = It, where Q is the total charge, I is the current, and t is the time.
Given: I = 0.5 A (Ampere is the unit of current) t = 1 hour = 3600 seconds (since 1 hour = 60 minutes = 60 * 60 = 3600 seconds)
Substituting the given values into the formula, we get:
Q = 0.5 A * 3600 s = 1800 C
So, the total charge passing through the light bulb in one hour is 1800 C. Therefore, the correct answer is E. 1800 C.
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