Iron (III) chloride reacts with dihydrogen monosulfide to produce iron (II) chloride, hydrogen monochloride and sulfur

To answer the question, we need to understand the chemical equation for the reaction between iron (III) chloride and dihydrogen monosulfide. The equation is as follows:

FeCl3 + H2S -> FeCl2 + HCl + S

Now, let's break down the reaction step by step:

Step 1: Identify the reactants and products:

• Reactants: Iron (III) chloride (FeCl3) and dihydrogen monosulfide (H2S)
• Products: Iron (II) chloride (FeCl2), hydrogen monochloride (HCl), and sulfur (S)

Step 2: Balance the equation: The equation is already balanced, as the number of atoms of each element is the same on both sides of the equation.

Step 3: Determine the type of reaction: This is a double displacement reaction, also known as a precipitation reaction, where the cations and anions of the reactants switch places to form new compounds.

Step 4: Write the balanced equation: FeCl3 + H2S -> FeCl2 + HCl + S

Step 5: Interpret the equation: When iron (III) chloride reacts with dihydrogen monosulfide, it forms iron (II) chloride, hydrogen monochloride, and sulfur.

Overall, the reaction between iron (III) chloride and dihydrogen monosulfide results in the formation of iron (II) chloride, hydrogen monochloride, and sulfur.