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How many kg of rice, of cost 9 Rs/kg must be mixed with 27 kg of rice of cost 7 Rs/kgget a gain of 10 % by selling the mixture at 9.24 Rs/kg

Question

How many kg of rice, of cost 9 Rs/kg must be mixed with 27 kg of rice of cost 7 Rs/kg to get a gain of 10 % by selling the mixture at 9.24 Rs/kg?

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Solution

Let's denote the amount of rice that costs 9 Rs/kg as x kg.

The cost price of the mixture is the sum of the cost of the 27 kg rice that costs 7 Rs/kg and the cost of the x kg rice that costs 9 Rs/kg. So, the cost price of the mixture is 277 + 9x = 189 + 9x Rs.

The selling price of the mixture is 9.24 Rs/kg. Since there is a gain of 10%, the cost price of the mixture is 90% of the selling price. So, 189 + 9x = 0.9 * 9.24 * (27 + x).

Solving this equation for x gives us the amount of rice that costs 9 Rs/kg that must be mixed with the 27 kg of rice that costs 7 Rs/kg to get a gain of 10% by selling the mixture at 9.24 Rs/kg.

Let's solve this equation:

189 + 9x = 0.9 * 9.24 * (27 + x) 189 + 9x = 8.316 * (27 + x) 189 + 9x = 224.532 + 8.316x 0.684x = 35.532 x = 35.532 / 0.684 x = 51.96 kg

So, approximately 52 kg of rice that costs 9 Rs/kg must be mixed with the 27 kg of rice that costs 7 Rs/kg to get a gain of 10% by selling the mixture at 9.24 Rs/kg.

This problem has been solved

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