The center of mass (COM) of a system is given by the formula:

COM = (m1*x1 + m2*x2 + m3*x3) / (m1 + m2 + m3)

where m1, m2, m3 are the masses and x1, x2, x3 are their respective distances from the origin.

Here, m1 = 2 kg, m2 = 3 kg, m3 = 6 kg and x1 = 0 cm, x2 = 5 cm, x3 = 10 cm.

Substituting these values into the formula, we get:

COM = (2*0 + 3*5 + 6*10) / (2 + 3 + 6)
= (0 + 15 + 60) / 11
= 75 / 11
= 6.82 cm

So, the center of mass of the system is 6.82 cm from the origin.

Question

The center of mass (COM) of a system is given by the formula:

COM = (m1*x1 + m2*x2 + m3*x3) / (m1 + m2 + m3)

where m1, m2, m3 are the masses and x1, x2, x3 are their respective distances from the origin.

Here, m1 = 2 kg, m2 = 3 kg, m3 = 6 kg and x1 = 0 cm, x2 = 5 cm, x3 = 10 cm.

Substituting these values into the formula, we get:

COM = (2*0 + 3*5 + 6*10) / (2 + 3 + 6)
    = (0 + 15 + 60) / 11
    = 75 / 11
    = 6.82 cm

So, the center of mass of the system is 6.82 cm from the origin.

Knowee AI · Accepted Answer

The center of mass (COM) of a system is given by the formula:

COM = (m1*x1 + m2*x2 + m3*x3) / (m1 + m2 + m3)

where m1, m2, m3 are the masses and x1, x2, x3 are their respective distances from the origin.

Here, m1 = 2 kg, m2 = 3 kg, m3 = 6 kg and x1 = 0 cm, x2 = 5 cm, x3 = 10 cm.

Substituting these values into the formula, we get:

COM = (2*0 + 3*5 + 6*10) / (2 + 3 + 6)
    = (0 + 15 + 60) / 11
    = 75 / 11
    = 6.82 cm

So, the center of mass of the system is 6.82 cm from the origin.

2 kg at origin, 3 kg at x=5 cm, and 6 kg at x=10 cm. The distance of the centre of mass of the system from the origin is