Find the smallest number such that when divided by 12, 18, 21 and 28, it leaves remainder 3 in each case?a.1012b.1010c.1011d.1009
Question
Solution 1
The smallest number that leaves a remainder of 3 when divided by 12, 18, 21, and 28 is found by:
Step 1: Find the least common multiple (LCM) of the four numbers. The LCM of 12, 18, 21, and 28 is 252.
Step 2: Add the remainder to the LCM. The remainder is 3, so 252 + 3 = 255.
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