A capacitor of capacitance 10 µF is charged to a potential of 50 V. The energy stored in the capacitor is:a) 12.5 Jb) 1.25 Jc) 0.125 Jd) 25 J
Question
A capacitor of capacitance 10 µF is charged to a potential of 50 V. The energy stored in the capacitor is:
a) 12.5 J
b) 1.25 J
c) 0.125 J
d) 25 J
Solution
The energy (W) stored in a capacitor can be calculated using the formula:
W = 1/2 * C * V^2
where: C is the capacitance, which is 10 µF or 10 * 10^-6 F V is the voltage, which is 50 V
Substituting these values into the formula gives:
W = 1/2 * 10 * 10^-6 F * (50 V)^2 W = 1/2 * 10 * 10^-6 F * 2500 V^2 W = 1.25 Joules
So, the energy stored in the capacitor is 1.25 J. Therefore, the correct answer is (b) 1.25 J.
Similar Questions
Capacity of a capacitor is 50 𝜇𝐹 . When it is charged from 10 mC to 50 mC, find the change in theenergy stored
A capacitor of capacitance 20 µF is charged to a potential difference of 500 V. The charge stored in the capacitor is:a) 1000 µCb) 10000 µCc) 0.1 Cd) 10 C
Given a potential of V= 24 V across a capacitor which has a capacitance of C = 2 micro Farads, what is the energy stored by the capacitor in Joules?
The potential difference across the plates of a capacitor is 200 V and the charge stored is 4 µC. The capacitance is:a) 20 µFb) 2 µFc) 0.02 µFd) 0.2 µF
or the circuit shown below, calculate the initial energy stored in the capacitor.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.