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Find the product. Write any variables in alphabetical order. (2q+5r)(2q−5r)2𝑞+5𝑟2𝑞-5𝑟

Question

Find the product. Write any variables in alphabetical order.

(2q+5r)(2q5r)(2q + 5r)(2q - 5r)

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Solution

1. Break Down the Problem

We need to find the product of the expression (2q+5r)(2q5r)(2q + 5r)(2q - 5r). This expression can be solved using the difference of squares formula, which is given as: a2b2=(a+b)(ab) a^2 - b^2 = (a + b)(a - b) In our case, we can identify a=2qa = 2q and b=5rb = 5r.

2. Relevant Concepts

Using the difference of squares formula, we can rewrite the expression as: (2q+5r)(2q5r)=(2q)2(5r)2 (2q + 5r)(2q - 5r) = (2q)^2 - (5r)^2

3. Analysis and Detail

Now, we will calculate (2q)2(2q)^2 and (5r)2(5r)^2:

  1. Calculate (2q)2(2q)^2: (2q)2=4q2 (2q)^2 = 4q^2
  2. Calculate (5r)2(5r)^2: (5r)2=25r2 (5r)^2 = 25r^2 Now substitute back into the equation: (2q+5r)(2q5r)=4q225r2 (2q + 5r)(2q - 5r) = 4q^2 - 25r^2

4. Verify and Summarize

We have derived the expression step by step. The difference of squares was applicable, and both squares were calculated correctly.

Final Answer

The product of (2q+5r)(2q5r)(2q + 5r)(2q - 5r) is: 4q225r2 4q^2 - 25r^2

This problem has been solved

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