I drop a 60-g golf ball from 2.0 m high. It rebounds to 1.3 m. How much energy is lost?Select one:a.0.41 Jb.0.29 Jc.0.88 Jd.1.0 J
Question
I drop a 60-g golf ball from 2.0 m high. It rebounds to 1.3 m. How much energy is lost?
Select one:
- a. 0.41 J
- b. 0.29 J
- c. 0.88 J
- d. 1.0 J
Solution
To solve this problem, we first need to calculate the initial potential energy of the golf ball and then the final potential energy after it rebounds. The difference between these two values will give us the energy lost.
Step 1: Calculate the initial potential energy (PE_initial) The formula for potential energy is PE = mgh, where m is mass, g is the acceleration due to gravity, and h is height.
Given: m = 60 g = 0.06 kg (since 1 kg = 1000 g) g = 9.8 m/s^2 h = 2.0 m
PE_initial = mgh = 0.06 kg * 9.8 m/s^2 * 2.0 m = 1.176 Joules
Step 2: Calculate the final potential energy (PE_final) The height after the ball rebounds is 1.3 m.
PE_final = mgh = 0.06 kg * 9.8 m/s^2 * 1.3 m = 0.7644 Joules
Step 3: Calculate the energy lost The energy lost is the difference between the initial and final potential energies.
Energy lost = PE_initial - PE_final = 1.176 Joules - 0.7644 Joules = 0.4116 Joules
So, the energy lost is approximately 0.41 Joules. Therefore, the answer is a. 0.41 J.
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