A 100 V ac circuit contains 3 Ω resistance and 4 Ω reactance in series. What would be the reactive power supplied by source?

To find the reactive power supplied by the source, we first need to find the current in the circuit.

Step 1: Find the total impedance (Z) of the circuit. The impedance of a series circuit is the square root of the sum of the squares of the resistance (R) and reactance (X).

Z = sqrt(R^2 + X^2) Z = sqrt((3 Ω)^2 + (4 Ω)^2) Z = 5 Ω

Step 2: Find the current (I) in the circuit. The current is the voltage (V) divided by the impedance (Z).

I = V / Z I = 100 V / 5 Ω I = 20 A

Step 3: Find the reactive power (Q). The reactive power is the product of the voltage (V), current (I), and the sine of the phase angle (θ). The phase angle is the arctangent of the reactance divided by the resistance.

θ = arctan(X / R) θ = arctan(4 Ω / 3 Ω) θ = 53.13°

Q = V * I * sin(θ) Q = 100 V * 20 A * sin(53.13°) Q = 1600 VAR

So, the reactive power supplied by the source is 1600 VAR.