An oak dresser has a density of 660kilogramspercubic meter and a volume of 0.15cubic meters. Calculate its mass.Write your answer as a whole number.

1. Break Down the Problem

To calculate the mass of the oak dresser, we need to use the formula: $\text{Mass} = \text{Density} \times \text{Volume}$ The problem provides the density and the volume of the dresser.

2. Relevant Concepts

• Density ($\rho$): The mass per unit volume of a substance, expressed in kilograms per cubic meter (kg/m³).
• Volume (V): The space occupied by the substance, expressed in cubic meters (m³).
• Mass (m): The amount of substance, expressed in kilograms (kg).

3. Analysis and Detail

Given:

• Density $\rho = 660 \, \text{kg/m}^3$
• Volume $V = 0.15 \, \text{m}^3$

Substituting the values into the mass formula: $m = 660 \, \text{kg/m}^3 \times 0.15 \, \text{m}^3$

Calculating the product: $m = 660 \times 0.15 = 99 \, \text{kg}$

4. Verify and Summarize

The calculations show that the mass of the oak dresser is 99 kg. There are no inconsistencies in the calculations, and the formula has been applied correctly.

Final Answer

The mass of the oak dresser is $\mathbf{99}$ kg.