In how many ways can 8 Indians and, 4 American and 4 Englishman can be seated in a row so that all persons of same nationality sit together?

To find the number of ways in which the Indians, Americans, and Englishmen can be seated together, we can treat each group as a single entity.

First, let's consider the Indians as a single entity. There are 8 Indians, so they can be arranged among themselves in 8! (8 factorial) ways.

Next, let's consider the Americans as a single entity. There are 4 Americans, so they can be arranged among themselves in 4! ways.

Similarly, the 4 Englishmen can be arranged among themselves in 4! ways.

Now, we have 3 entities - the group of Indians, the group of Americans, and the group of Englishmen. These 3 entities can be arranged among themselves in 3! ways.

Finally, we multiply all the possibilities together to get the total number of ways:

8! * 4! * 4! * 3! = 40,320 * 24 * 24 * 6 = 185,794,560

Therefore, there are 185,794,560 ways in which the Indians, Americans, and Englishmen can be seated together in a row.