What is the probability of rolling getting exactly 3 heads when tossing a coin 5 times?

This is a binomial probability problem. The formula for binomial probability is:

P(X=k) = C(n, k) * (p^k) * ((1-p)^(n-k))

where:

• P(X=k) is the probability of k successes in n trials
• C(n, k) is the number of combinations of n items taken k at a time
• p is the probability of success on a single trial
• n is the number of trials
• k is the number of successes

In this case:

• n = 5 (the number of coin tosses)
• k = 3 (the number of heads we want to get)
• p = 0.5 (the probability of getting a head in a single toss)

Substituting these values into the formula, we get:

P(X=3) = C(5, 3) * (0.5^3) * ((1-0.5)^(5-3))

Calculating the above expression gives a probability of 0.3125.

So, the probability of getting exactly 3 heads when tossing a coin 5 times is 0.3125.