What is the output of this program? Integer i = new Integer(257); byte x = i.byteValue(); System.out.print(x);Select one:25710256
Question
What is the output of this program?
Integer i = new Integer(257);
byte x = i.byteValue();
System.out.print(x);
Select one:
- 257
- 102
- 56
Solution
The output of this program will be 1.
Here's the step by step explanation:
-
An Integer object is created with the value 257.
-
The byteValue() method is called on the Integer object. This method converts the value of this Integer to a byte.
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The byte data type in Java is 8-bit signed two's complement integer, which has a minimum value of -128 and a maximum value of 127 (inclusive).
-
When 257 is converted to byte, it exceeds the maximum limit of byte. So, it wraps around from the minimum value.
-
257 is 1 more than the maximum byte value of 256 (256 is calculated as 128 + 128 - 1), so it wraps around to 1.
-
The value 1 is printed to the console.
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