To determine if (x-5) is a factor of the polynomial p(x) = x³ - 7x² + 16x - 12, we can use the Factor Theorem. The Factor Theorem states that a polynomial f(x) has a factor (x - k) if and only if f(k) = 0.

In this case, we want to find out if (x - 5) is a factor of the polynomial, so we substitute x = 5 into the polynomial. If p(5) = 0, then (x - 5) is a factor of the polynomial.

Let's substitute x = 5 into the polynomial:

p(5) = 5³ - 7*5² + 16*5 - 12
= 125 - 175 + 80 - 12
= 18

Since p(5) ≠ 0, we can conclude that (x - 5) is not a factor of the polynomial p(x) = x³ - 7x² + 16x - 12.

Question

To determine if (x-5) is a factor of the polynomial p(x) = x³ - 7x² + 16x - 12, we can use the Factor Theorem. The Factor Theorem states that a polynomial f(x) has a factor (x - k) if and only if f(k) = 0.

In this case, we want to find out if (x - 5) is a factor of the polynomial, so we substitute x = 5 into the polynomial. If p(5) = 0, then (x - 5) is a factor of the polynomial.

Let's substitute x = 5 into the polynomial:

p(5) = 5³ - 7*5² + 16*5 - 12
     = 125 - 175 + 80 - 12
     = 18

Since p(5) ≠ 0, we can conclude that (x - 5) is not a factor of the polynomial p(x) = x³ - 7x² + 16x - 12.

Knowee AI · Accepted Answer

To determine if (x-5) is a factor of the polynomial p(x) = x³ - 7x² + 16x - 12, we can use the Factor Theorem. The Factor Theorem states that a polynomial f(x) has a factor (x - k) if and only if f(k) = 0.

In this case, we want to find out if (x - 5) is a factor of the polynomial, so we substitute x = 5 into the polynomial. If p(5) = 0, then (x - 5) is a factor of the polynomial.

Let's substitute x = 5 into the polynomial:

p(5) = 5³ - 7*5² + 16*5 - 12
     = 125 - 175 + 80 - 12
     = 18

Since p(5) ≠ 0, we can conclude that (x - 5) is not a factor of the polynomial p(x) = x³ - 7x² + 16x - 12.

Without actually finding p(5), find whether (x–5) is a factor of p (x) = x3 – 7x2 +16x – 12. Justify your answer.

Question

Without actually finding p(5), find whether (x–5) is a factor of

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