Knowee
Questions
Features
Study Tools

Consider the line =+9x8y−7.What is the slope of a line parallel to this line?What is the slope of a line perpendicular to this line?

Question

Consider the line = +9x8y−7.

What is the slope of a line parallel to this line?

What is the slope of a line perpendicular to this line?

🧐 Not the exact question you are looking for?Go ask a question

Solution

To find the slope of a line parallel to the given line, we need to determine the slope of the given line. The given line is in the form of y = mx + b, where m represents the slope.

In this case, the given line is 9x + 8y - 7 = 0. To find the slope, we need to rearrange the equation in the form of y = mx + b.

First, let's isolate the term with y by subtracting 9x and 7 from both sides of the equation:

8y = -9x + 7

Next, divide both sides of the equation by 8 to solve for y:

y = (-9/8)x + 7/8

Now we can see that the slope of the given line is -9/8.

Since parallel lines have the same slope, the slope of any line parallel to the given line will also be -9/8.

To find the slope of a line perpendicular to the given line, we need to find the negative reciprocal of the slope of the given line.

The negative reciprocal of -9/8 is 8/9.

Therefore, the slope of a line perpendicular to the given line is 8/9.

This problem has been solved

Similar Questions

What is the slope of a line perpendicular to the line defined by y = 2.5x - 1.7 ?

A line has a y-intercept of 5 and is parallel to the line represented by the equation 2x + 3y = 9. Which of the following equations represents the line?

Line u passes through points (8, 7) and (2, 14). Line v is perpendicular to u. What is the slope of line v?

Find the slope of a line perpendicular to the line whose equation is 3, x, minus, 3, y, equals, 453x−3y=45. Fully simplify your answer.

Find the slope of a line parallel to the line whose equation is 6, x, minus, 10, y, equals, minus, 1006x−10y=−100. Fully simplify your answer

1/3

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.