When solving a system of equations algebraically, which statement results in no solution?
Question
When solving a system of equations algebraically, which statement results in no solution?
Solution
When solving a system of equations algebraically, the statement that results in no solution is when the two equations, after being simplified, turn into the same line (same slope and same y-intercept) but are set to equal different y-values.
For example, consider the following system of equations:
- 2x + 3y = 6
- 4x + 6y = 12
If we divide the second equation by 2, we get:
2x + 3y = 6
which is the same as the first equation. However, if we had a system like:
- 2x + 3y = 6
- 4x + 6y = 13
Even after simplifying the second equation, we would get 2x + 3y = 6.5, which is not the same as the first equation. This would mean that the two lines represented by these equations are parallel and do not intersect, hence there is no solution to this system of equations.
Similar Questions
Consider the given system of equations. If is the solution to the system, then what is the value of ?
If and are distinct solutions to the system of equations shown, what is the product of the and ?
In the system of equations, is a constant. For what value of does the system of linear equations have no solutions?
Context: iven system of equations: (3x - 5y - 4 = 0) (Equation 1) (9x - 2y - 7 = 0) (Equation 2) Improve writing7
5𝑥−𝑦=2𝑦+45x−y=2y+4𝑏𝑦=3+5𝑥by=3+5xIn the given system of equations, 𝑏b is a constant. If the system has no solution, what is the value of 𝑏b?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.