An Icebag of density 900kg/m3 is floating in water of density 1000 kg/m3. The percentage of volume of ice cube outside the water is

To solve this problem, we need to use the principle of flotation, which states that when a body is floating, the weight of the body is equal to the weight of the fluid displaced by it.

Step 1: Identify the given values. Density of ice, ρ1 = 900 kg/m³ Density of water, ρ2 = 1000 kg/m³

Step 2: Use the formula for the fraction of the volume of the ice cube that is submerged, which is given by the ratio of the density of the ice to the density of the water. V_submerged/V_total = ρ1/ρ2 = 900/1000 = 0.9

This means that 90% of the volume of the ice cube is submerged in the water.

Step 3: To find the percentage of the volume of the ice cube that is outside the water, subtract the percentage that is submerged from 100%. V_outside = 100% - V_submerged = 100% - 90% = 10%

So, 10% of the volume of the ice cube is outside the water.