If the input in BPF (experiment 6) is 0.3V p-p sine wave, what is the maximum p-p final output we can expect?

To address the question of the maximum peak-to-peak (p-p) final output from a Band-Pass Filter (BPF) when given an input of 0.3V p-p sine wave, follow these steps:

1. ### Break Down the Problem

We need to analyze how the BPF will affect the input signal's amplitude. Specifically, we will look into:

1. The characteristics of the BPF.
2. The relationship between input and output voltages considering the filter's frequency response.

2. ### Relevant Concepts

• A Band-Pass Filter allows signals within a certain frequency range to pass while attenuating signals outside that range.
• The gain of the filter at the specific frequency of interest will determine how much of the input voltage appears at the output.

3. ### Analysis and Detail

1. Input Voltage: The input sine wave is $V_{in(p-p)} = 0.3 V_{p-p}$.
2. BPF Gain: If the BPF is designed to pass frequencies around the input frequency with an ideal gain of 1 (0 dB), the output will be equal to the input.
3. The output voltage can be influenced by the BPF's quality factor (Q) and its gain at a specific frequency. However, for simplicity, let's assume that:
   • At the desired frequency, the filter has a gain of approximately 1.

Thus, under ideal conditions, the maximum output voltage will also have a peak-to-peak value the same as the input.

4. ### Verify and Summarize

The expected output peak-to-peak voltage is:

• Since $V_{out(p-p)} \approx V_{in(p-p)}$ when the input frequency lies within the bandwidth of the filter.

Final Answer

Thus, the maximum peak-to-peak final output we can expect is $0.3 V_{p-p}$ if the frequency of the input signal lies within the passband of the BPF.