The half-life of a radioactive kind of lead is 3 hours. If you start with 48,320 grams of it, how much will be left after 15 hours?

Sure, here's how you can solve this problem:

1. First, you need to determine how many half-lives have passed in 15 hours. Since the half-life of this radioactive lead is 3 hours, you would divide 15 by 3. This gives you 5 half-lives.

2. Next, you need to calculate how much of the radioactive lead remains after each half-life. After one half-life, half of the original amount remains. So, after one half-life, you would have 48,320 / 2 = 24,160 grams.

3. After two half-lives, half of the remaining amount from the first half-life remains. So, you would have 24,160 / 2 = 12,080 grams.

4. You would continue this process for the remaining half-lives. After three half-lives, you would have 12,080 / 2 = 6,040 grams. After four half-lives, you would have 6,040 / 2 = 3,020 grams. After five half-lives, you would have 3,020 / 2 = 1,510 grams.

So, after 15 hours, you would have 1,510 grams of the radioactive lead remaining.