# A car is traveling at 21.0 m/s. It slows to a stop at a constant rate over 5.00 s. How far does the car travel during those 5.00 seconds before it stops?

## Question

## Solution 1

To solve this problem, we can use the formula for distance traveled under constant acceleration (or deceleration in this case), which is:

d = vt + 0.5at^2

where:

- d is the distance traveled,
- v is the initial velocity,
- a is the acceleration (which will be negative since the car is slowing down Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

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