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Write the first six terms of the sequence.$a_n=3n-1$an​=3n−1​The first six terms of the sequence are , , , , ,

Question

Write the first six terms of the sequence.

The sequence is defined as:

an=3n1 a_n = 3n - 1

The first six terms of the sequence are , , , , , .

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Solution

To find the first six terms of the sequence defined by an=3n1 a_n = 3n - 1 , we will substitute the values of n n from 1 to 6 into the formula.

Step 1: Calculate Each Term

  1. For n=1 n = 1 : a1=3(1)1=31=2 a_1 = 3(1) - 1 = 3 - 1 = 2
  2. For n=2 n = 2 : a2=3(2)1=61=5 a_2 = 3(2) - 1 = 6 - 1 = 5
  3. For n=3 n = 3 : a3=3(3)1=91=8 a_3 = 3(3) - 1 = 9 - 1 = 8
  4. For n=4 n = 4 : a4=3(4)1=121=11 a_4 = 3(4) - 1 = 12 - 1 = 11
  5. For n=5 n = 5 : a5=3(5)1=151=14 a_5 = 3(5) - 1 = 15 - 1 = 14
  6. For n=6 n = 6 : a6=3(6)1=181=17 a_6 = 3(6) - 1 = 18 - 1 = 17

Final Answer

The first six terms of the sequence are: 2, 5, 8, 11, 14, 17.

This problem has been solved

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