# The ratio of ages of John and David is 3:4. Four years ago, the ratio of their ages was 2:3. How old is David now?

## Question

## Solution 1

Let's denote the current ages of John and David as 3x and 4x respectively.

Four years ago, John was 3x - 4 years old and David was 4x - 4 years old. According to the problem, the ratio of their ages at that time was 2:3.

So, we can set up the equation (3x - 4) / (4x - 4) = 2 / 3.

Cross-multiplyin Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.

```
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
```

## Similar Questions

The sum of the ages of John and Sarah is 26. Five years ago, John was three times as old as Sarah. How old is John now?a.9b.12c.17d.22

Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar's age at present?

Twelve years ago, Budh was twice as old as Badri. If the ratio of their present ages is 4:3 respectively, find the difference between their present ages.

Charlie's age is 23 of Charlotte's age now. 2 years ago, the ratio of Charlie's age to Charlotte's age was 3 : 5. How old is Charlotte now?

The present ages of A and B are in the ratio 3 : 4. Ten years ago, this ratio was 4 : 7. The present ages of A and B are respectively?

## Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.