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How many BCD adders would be required to add the numbers (973)10 + (39)10?(A) 3(B) 4(C) 5(D) 6

Question

How many BCD adders would be required to add the numbers (973)10 + (39)10?

(A) 3
(B) 4
(C) 5
(D) 6

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Solution

To solve this problem, we need to understand what a BCD (Binary Coded Decimal) adder is. A BCD adder is a circuit that adds two BCD digits together and outputs a BCD digit.

The numbers given in the problem are (973)10 and (39)10. These are decimal numbers, and the subscript 10 indicates the base, which is 10 in this case.

To convert these numbers to BCD, we represent each digit of the decimal number as a four-bit binary number.

So, (973)10 would be represented as 1001 0111 0011 in BCD and (39)10 would be represented as 0011 1001 in BCD.

Now, to add these two BCD numbers together, we would need a BCD adder for each digit.

Therefore, we would need 3 BCD adders for (973)10 and 2 BCD adders for (39)10, making a total of 5 BCD adders.

So, the answer is (C) 5.

This problem has been solved

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