What is the volume of 6 moles of argon gas in cm3 at room temperature and pressure?

To find the volume of 6 moles of argon gas at room temperature and pressure, we can use the ideal gas law. However, at room temperature and pressure (RTP), there's a simpler rule we can use: one mole of any gas occupies 24.0 dm^3.

Step 1: Identify the volume of one mole of gas at RTP. This is given as 24.0 dm^3.

Step 2: Multiply this volume by the number of moles. In this case, we have 6 moles of argon gas.

So, 24.0 dm^3/mole * 6 moles = 144 dm^3.

Step 3: Convert this volume from dm^3 to cm^3. We know that 1 dm^3 = 1000 cm^3.

So, 144 dm^3 * 1000 cm^3/dm^3 = 144,000 cm^3.

Therefore, the volume of 6 moles of argon gas at room temperature and pressure is 144,000 cm^3.