The maximum possible value of angle A in triangle ABC can be found using the law of cosines. The law of cosines states that c² = a² + b² - 2abcosC, where a, b, and c are the sides of the triangle and C is the angle opposite side c.

In this case, we have BC = 1, AC = 2, and we're looking for the maximum possible value of angle A. We can rearrange the law of cosines to solve for cosC:

cosC = (a² + b² - c²) / 2ab

Substituting the given values, we get:

cosA = (1² + 2² - 1²) / 2*1*2 = 2 / 4 = 0.5

Therefore, the maximum possible value of angle A is cos⁻¹(0.5) = 60 degrees.

Question

The maximum possible value of angle A in triangle ABC can be found using the law of cosines. The law of cosines states that c² = a² + b² - 2abcosC, where a, b, and c are the sides of the triangle and C is the angle opposite side c.

In this case, we have BC = 1, AC = 2, and we're looking for the maximum possible value of angle A. We can rearrange the law of cosines to solve for cosC:

cosC = (a² + b² - c²) / 2ab

Substituting the given values, we get:

cosA = (1² + 2² - 1²) / 2*1*2 = 2 / 4 = 0.5

Therefore, the maximum possible value of angle A is cos⁻¹(0.5) = 60 degrees.

Knowee AI · Accepted Answer

The maximum possible value of angle A in triangle ABC can be found using the law of cosines. The law of cosines states that c² = a² + b² - 2abcosC, where a, b, and c are the sides of the triangle and C is the angle opposite side c.

In this case, we have BC = 1, AC = 2, and we're looking for the maximum possible value of angle A. We can rearrange the law of cosines to solve for cosC:

cosC = (a² + b² - c²) / 2ab

Substituting the given values, we get:

cosA = (1² + 2² - 1²) / 2*1*2 = 2 / 4 = 0.5

Therefore, the maximum possible value of angle A is cos⁻¹(0.5) = 60 degrees.

In a triangle ABC if BC =1 and AC = 2. Then the maximum possible value of angle A is-

Question

In a triangle ABC if BC = 1 and AC = 2. Then the maximum possible value of angle A is-

Solution

Similar Questions

Upgrade your grade with Knowee