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If y is directly proportional to x2, and y = 2 when x = 1,what is the value of y when x = 5? y =

Question

If y is directly proportional to x², and y = 2 when x = 1, what is the value of y when x = 5?

y =  
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Solution

First, we need to understand the relationship between y and x. Since y is directly proportional to x^2, we can express this relationship as y = kx^2, where k is the constant of proportionality.

Next, we use the given values to find the constant of proportionality. We know that y = 2 when x = 1, so we can substitute these values into the equation:

2 = k(1)^2 2 = k

Now that we know k = 2, we can find the value of y when x = 5. We substitute these values into the equation:

y = 2(5)^2 y = 2 * 25 y = 50

So, when x = 5, y = 50.

This problem has been solved

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