If y varies directly with the square of x and y = 4.3 when x = 5, what is the value of y when x = 6?
Question
Solution 1
Step 1: Understand the problem. The problem states that y varies directly with the square of x. This means that y = kx^2, where k is the constant of variation.
Step 2: Find the constant of variation. We know that y = 4.3 when x = 5. So, we can substitute these values into the equation to find k:
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