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Solve this system of equations using substitution method.Must show work/steps on your work page {𝑦=3𝑥−44𝑥+3𝑦=1(, )

Question

Solve this system of equations using substitution method. Must show work/steps on your work page

\begin{align*} y &= 3x - 4 \ 4x + 3y &= 1 \end{align*}

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Solution

1. Break Down the Problem

We need to solve the system of equations given by:

  1. y=3x4 y = 3x - 4
  2. 4x+3y=1 4x + 3y = 1

We will use the substitution method, which involves substituting the expression for y y from the first equation into the second equation.

2. Relevant Concepts

The substitution method entails the following steps:

  • Isolate one variable in one of the equations.
  • Substitute that expression into the other equation.
  • Solve for the remaining variable.

3. Analysis and Detail

Step 1: Substitute y y

We take the expression for y y from the first equation and substitute it into the second equation: 4x+3(3x4)=1 4x + 3(3x - 4) = 1

Step 2: Simplify the Equation

Now, distribute the 3 3 : 4x+9x12=1 4x + 9x - 12 = 1

Combine like terms: 13x12=1 13x - 12 = 1

Step 3: Solve for x x

Now we isolate x x : 13x=1+12 13x = 1 + 12 13x=13 13x = 13 x=1 x = 1

Step 4: Find y y

Now that we have x x , we can use the first equation to find y y : y=3(1)4 y = 3(1) - 4 y=34 y = 3 - 4 y=1 y = -1

4. Verify and Summarize

We found x=1 x = 1 and y=1 y = -1 . Let's verify these values by substituting them back into the original equations:

  1. For y=3x4 y = 3x - 4 : 1=3(1)4(True) -1 = 3(1) - 4 \quad \text{(True)}
  2. For 4x+3y=1 4x + 3y = 1 : 4(1)+3(1)=1(True) 4(1) + 3(-1) = 1 \quad \text{(True)}

Both equations hold true.

Final Answer

The solution to the system of equations is: x=1,y=1 x = 1, \quad y = -1

This problem has been solved

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