How many different alkenes result when 2-bromooctane is treated with a strong base?Select answer from the options below1  2  3  4

The answer is 3.

Here's the step-by-step explanation:

1. The reaction described is an elimination reaction (E2), where a strong base is used to remove a proton from the carbon next to the one carrying the bromine atom in 2-bromooctane, leading to the formation of an alkene.

2. The bromine atom is on the second carbon of the octane chain. Therefore, the alkene can form at three different locations: between the first and second carbons, the second and third carbons, or the third and fourth carbons.

3. The alkene cannot form beyond the fourth carbon as it would not be in proximity to the bromine atom on the second carbon.

4. Therefore, three different alkenes can be formed when 2-bromooctane is treated with a strong base.