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Derive the expression for the electric field of a dipole at a point on the equatorial plane of the dipole.

Question

Derive the expression for the electric field of a dipole at a point on the equatorial plane of the dipole.

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Solution

Sure, let's derive the expression for the electric field of a dipole at a point on the equatorial plane of the dipole.

Step 1: Define the dipole A dipole consists of two equal and opposite charges, +q and -q, separated by a distance 2a. The dipole moment (p) is defined as the product of the charge and the separation distance, directed from the negative to the positive charge. So, p = q * 2a.

Step 2: Consider a point on the equatorial plane Let's consider a point P at a distance r from the center of the dipole on the equatorial plane. We want to find the electric field at this point.

Step 3: Calculate the electric field due to each charge The electric field at P due to the positive charge is directed away from it, and the electric field due to the negative charge is directed towards it. Since these two fields are in the same direction, they add up. The magnitude of the electric field due to each charge is given by Coulomb's law: E = k*q/r^2, where k is Coulomb's constant.

Step 4: Find the resultant electric field The resultant electric field at P is the vector sum of the two fields. Since they are in the same direction, this is simply 2E, or 2k*q/r^2.

Step 5: Express the electric field in terms of the dipole moment We can express the charge q in terms of the dipole moment p: q = p / 2a. Substituting this into the expression for the electric field gives E = kp / (ar^2).

Step 6: Final expression The final expression for the electric field of a dipole at a point on the equatorial plane is E = kp / (ar^2), directed along the line perpendicular to the dipole moment and passing through the center of the dipole.

This problem has been solved

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