How is memory allocated for an array dynamically in C++?int* arr = new int[10];int arr = new int[10];int arr[10] = new int;int* arr = alloc int[10];
Question
How is memory allocated for an array dynamically in C++?
int* arr = new int[10];
int arr = new int[10];
int arr[10] = new int;
int* arr = alloc int[10];
Solution
In C++, dynamic memory allocation for an array can be done using the 'new' operator. Here is the step by step process:
- Declare a pointer: First, you need to declare a pointer of the type of array you want to create. For example, if you want to create an array of integers, you would declare an integer pointer.
int* arr;
- Allocate memory: Next, you use the 'new' operator to allocate memory for the array. The 'new' operator returns a pointer to the first element of the array. You need to specify the number of elements that the array should hold inside square brackets.
arr = new int[10];
In this case, memory for 10 integers is allocated and the address of the first element is assigned to the 'arr' pointer. Now, 'arr' can be used like a normal array.
The other lines of code you provided are incorrect:
int arr = new int[10];
is incorrect because 'arr' is not a pointer.int arr[10] = new int;
is incorrect because you're trying to assign a pointer to an array.int* arr = alloc int[10];
is incorrect because 'alloc' is not a valid keyword in C++. You should use 'new' instead.
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