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2) Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas.

Question

2) Aluminum bromide and chlorine gas react to form aluminum chloride and bromine gas.

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Solution

Sure, here is the step by step process of the reaction:

  1. Write down the unbalanced equation: AlBr3 + Cl2 -> AlCl3 + Br2

  2. Balance the equation. In this case, the equation is already balanced.

  3. Interpret the equation in terms of moles. In this reaction, one mole of aluminum bromide reacts with one mole of chlorine gas to produce one mole of aluminum chloride and one mole of bromine gas.

  4. If needed, convert the amounts of reactants and products from moles to masses, and vice versa, using molar masses.

  5. If the problem involves reaction conditions, use the ideal gas law or other gas laws to convert between volumes, pressures, and temperatures.

Remember, always make sure your equation is balanced before you start making calculations.

This problem has been solved

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