CB is the diameter of this circle and its radius is 1.13 cm.AC = 1.82 cmThe length of AB correct to one decimal place is: 5.1 3.3 1.8 1.3
Question
CB is the diameter of this circle and its radius is 1.13 cm.
AC = 1.82 cm
The length of AB correct to one decimal place is:
- 5.1
- 3.3
- 1.8
- 1.3
Solution
The problem you've presented is a geometry problem involving a circle and a triangle. Here's how you can solve it:
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First, understand the problem. You have a circle with a diameter CB and a radius of 1.13 cm. AC is a line segment that measures 1.82 cm. You're asked to find the length of AB.
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Since CB is the diameter, the length of CB is twice the radius, which is 2 * 1.13 cm = 2.26 cm.
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Now, you have a triangle ABC, where CB is the hypotenuse (since it's the diameter of the circle), AC is one side, and you're asked to find AB.
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You can use the Pythagorean theorem to solve this, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides. In mathematical terms, this is: a² + b² = c².
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In your case, c (the hypotenuse) is CB, a is AC, and b is AB (which you're trying to find). So, you can set up the equation as follows: (1.82 cm)² + (AB)² = (2.26 cm)².
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Solve for AB: (AB)² = (2.26 cm)² - (1.82 cm)² = 5.1076 cm² - 3.3124 cm² = 1.7952 cm².
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Take the square root of both sides to solve for AB: AB = sqrt(1.7952 cm²) = 1.34 cm.
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However, you're asked to provide the answer correct to one decimal place. So, round 1.34 cm to 1.3 cm.
So, the length of AB, correct to one decimal place, is 1.3 cm.
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