For an inputs key of size 128 bits constituting of all zeros, what is w(7) ?Group of answer choices{62 63 63 63}{62 62 62 62}{00 00 00 00}{63 63 63 62}

The question seems to be related to the AES (Advanced Encryption Standard) key schedule, which is a part of the AES encryption process. The key schedule generates a series of round keys from the initial cipher key. These round keys are represented as w[i], where i is the round number.

In AES, the key size can be 128, 192, or 256 bits. In this case, we have a 128-bit key consisting of all zeros.

The w(7) represents the 7th word in the key schedule. For a 128-bit key, the key schedule starts by simply copying the cipher key to the first four words of the expanded key (w[0] to w[3]).

The generation of further words (w[i] for i > 3) involves several transformations: SubWord, RotWord, and an XOR operation with a round constant (Rcon). However, since the initial key consists of all zeros, all these operations will also result in zeros.

Therefore, w(7) for an input key of size 128 bits consisting of all zeros will be {00 00 00 00}.