There are 6 men and 7 women. In how many ways a committee of 4 members can be made such that a particular woman is always excluded?

To solve this problem, we first need to understand that there are 6 men and 6 women available for selection (since one particular woman is always excluded).

Step 1: Identify the total number of people available for selection. This is 6 men + 6 women = 12 people.

Step 2: Calculate the number of ways to select a committee of 4 members from these 12 people. This can be done using the combination formula, which is nCr = n! / [(n-r)! * r!], where n is the total number of items, r is the number of items to choose, and "!" denotes factorial.

So, the number of ways to select a committee of 4 members from 12 people is 12C4 = 12! / [(12-4)! * 4!] = 495 ways.

So, there are 495 ways to form a committee of 4 members such that a particular woman is always excluded.