In how many ways can the letters of the word "SUCCESS" be arranged if the two S's cannot be together?Choices:- 7!/2! - 6! 7!−6! 7!−2! 7!−5!

To solve this problem, we first need to find the total number of ways the letters can be arranged without any restrictions. Then we subtract the number of ways the letters can be arranged with the two S's together.

1. The word "SUCCESS" has 7 letters, but the letters S, C, and U are repeated. So, the total number of ways the letters can be arranged without any restrictions is 7!/(3!2!2!) = 420 ways.

2. To find the number of ways the letters can be arranged with the two S's together, we can treat the two S's as one letter. So, we now have 6 letters (the two S's, U, C, C, E). Again, the letters S, C, and U are repeated. So, the total number of ways these letters can be arranged is 6!/(2!2!) = 180 ways.

3. Finally, subtract the number of ways the letters can be arranged with the two S's together from the total number of ways the letters can be arranged without any restrictions. So, the answer is 420 - 180 = 240 ways.

Therefore, none of the given choices are correct.