How many ways are there to permute the 8 letters A, B, C, D, E, F, G, H so that A is not at the beginning and H is not at the end?
Question
Solution 1
To solve this problem, we need to use the concept of permutations in combinatorics.
First, let's consider the total number of permutations of 8 distinct letters, which is 8!.
Then, we need to subtract the cases where A is at the beginning and H is at the end.
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