Given (x4 + 2y) dx - xdy =0, using FOLDE, the integrating factor isQuestion 8Select one:a.e -xb.xc.x -2d.x2e.ex

The given differential equation is in the form of Mdx + Ndy = 0, where M = x^4 + 2y and N = -x.

The condition for exactness is (dN/dx) = (dM/dy).

Here, (dN/dx) = -1 and (dM/dy) = 2.

Since (dN/dx) ≠ (dM/dy), the given differential equation is not exact.

For a non-exact differential equation, we can find an integrating factor to make it exact.

The formula for the integrating factor in this case is e^(∫(dM/dy - dN/dx) dy).

Substituting the values, we get e^(∫(2 - (-1)) dy) = e^(3y).

So, the integrating factor is e^(3y).

However, this option is not given in the choices. There might be a mistake in the question or the provided options.