Given (x4 + 2y) dx - xdy =0, using FOLDE, the integrating factor isQuestion 1Select one:a.xb.x -2c.exd.e -xe.x2

The given differential equation is in the form of Mdx + Ndy = 0, where M = x^4 + 2y and N = -x.

The condition for exactness is (dN/dx - dM/dy) / M = R(x), where R(x) is a function of x only.

Calculating dN/dx gives -1 and dM/dy gives 2.

Substituting these values into the condition for exactness gives (-1 - 2) / (x^4 + 2y) = -3 / (x^4 + 2y) = R(x).

Since R(x) is not a function of x only, the given differential equation is not exact.

However, we can make it exact by multiplying by an integrating factor.

The integrating factor is e^(∫R(x) dx).

Substituting R(x) = -3 / (x^4 + 2y) into the formula for the integrating factor gives e^(∫-3 / (x^4 + 2y) dx).

This integral is not easily solvable, so the integrating factor cannot be determined from the given options.

Therefore, none of the options a, b, c, d, or e is the correct answer.